指针、结构、联合和枚举（Pointers, structures, unions, and enumerations）.docVIP

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指针、结构、联合和枚举（Pointers, structures, unions, and enumerations）.doc

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指针、结构、联合和枚举（Pointers, structures, unions, and enumerations）.doc

指针、结构、联合和枚举（Pointers, structures, unions, and enumerations） Int, i=200, x; Int *ip; We define two integer variables, I, x, and also define a pointer variable IP to integer. I, X You can store integers, whereas in IP you can only store the addresses of integer variables. We can assign the address of I to ip: Ip=i; At this point, the pointer variable IP points to the integer variable I, and assumes that the variable I has an address of 1800. This assignment can be interpreted in an image For the links shown below. IP I Metaprotein - - - - - - - - metaprotein 1800 - to 200 offers offers offers L - L - - - Figure 1. gives the pointer variable assignment Later, we can access the variable I indirectly through pointer variable IP, for example: X=*ip; The operator * accesses the storage area with IP as the address, while the IP stores the address of the variable I, so *ip Access is the storage area of address 1800 (because it is an integer, actually two bytes starting from 1800), It is the storage area that I occupies, so the assignment expression above is equivalent to X=i; In addition, pointer variables are the same as ordinary variables, and the values stored in them can be changed It means that they can change their direction, assuming Int, I, J, *p1, *p2; I=a; J=b; P1=i; P2=j; Set up the links shown below: P1 I Metaprotein - - - - - - - - metaprotein -aoffers offers offers to L - L - - - P2 I Metaprotein - - - - - - - - metaprotein -boffers offers offers to L - L - - - Figure 2. assignment results Assignment expression: P2=p1 Make P2 and P1 point to the same object I, when *p2 is equivalent to I instead of J, and figure 2. becomes shown in figure 3: P1 I Metaprotein - - - - - - - - metaprotein -aoffers offers offers to L - -, L - - chrysene P2 / J Metaprotein - - - - - - - -, metaprotein - boffers offers offers L - L - - - Figure 3. the situation at p2=p1 If the following expression is executed: *p2=*p1; This means that the content assigned by the P1 is assigned to the