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高一物理必修一公式(High physics required one formula) High physics required one formula I. the motion of a particle (1) -- rectilinear motion 1) uniform variable linear motion 1. average speed V flat =S/t (definition) 2. useful inferences Vt^2 - Vo^2=2as 3. middle speed Vt/2=V flat = (Vt+Vo) /2 4. end velocity Vt=Vo+at 5. middle position speed Vs/2=[(Vo^2 +Vt^2) /2]1/2 6. displacement S=, V flat t=Vot + at^2/2=Vt/2t 7. acceleration a= (Vt-Vo) /t to Vo is positive direction, a and Vo same direction (acceleration) a0; reverse is a0 8. the experiment uses the inference that the delta S=aT^2, Delta S is the difference between the displacements in the adjacent continuous equal time (T) 9. main physical quantities and units: initial velocity (Vo): m/s Acceleration (a): m/s^2 end velocity (Vt): m/s Time (T): s displacement (S): m (m) distance: m speed unit conversion: 1m/s=3.6Km/h Note: (1) the average speed is a vector. (2) the object is very large and the acceleration is not necessarily large. (3) a= (Vt-Vo) /t is just a measure, not a decision. (4) other relevant content: particle / displacement and distance, /s--t diagram, /v--t diagram / velocity and rate 2) free fall 1. initial speed Vo=0 2. terminal speed Vt=gt 3. drop height h=gt^2/2 (down from the Vo position) 4. inference Vt^2=2gh Note: (1) free fall motion is a uniformly accelerated linear motion with zero initial velocity, followed by uniform velocity and linear motion. (2) a=g=9.8 m/s^2 10m/s^2 is the acceleration of gravity at the equator is smaller in the mountains than plains, vertical direction. 3) vertical projectile 1. S=Vot- gt^2/2 2. at the end of displacement speed of Vt= Vo- GT (g=9.8 = 10m/s2) 3. useful inferences Vt^2 - Vo^2=-2gS 4. rises maximum height Hm=Vo^2/2g (throw points count) 5. round-trip time t=2Vo/g (time from the throw back to the original position) Note: (1) the whole process is a uniform deceleration linear motion, in which the upward direction is positive, and the acceleration is negative. (
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