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高一物理公式及其推论(Physics formula of high one and its inference) First, the motion of a particle (1) ---- linear motion 1) uniform variable linear motion 1. average speed V flat =S / T (definition type) 2. useful inference Vt 2 - V0 2=2as 3. middle time speed Vt / 2= V flat = (V T + V o) / 2 4. terminal speed V=Vo+at 5. middle position speed Vs / 2=[(V_o2 + V_t2) / 2] 1/2 6. displacement, S=, V, flat, t=V, O, t + at2 / 2=V T / 2 T 7. acceleration a= (V_t - V_o) / T with V_o in the positive direction, a and V_o same direction (acceleration) a0; reverse is a0 8. the experiment uses the inference that the delta S=aT2, Delta S is the difference between the displacements in the adjacent continuous equal time (T) 9. main physical quantities and units: initial velocity (V_o): m/, s acceleration (a): m/, S2 end velocity (Vt): m/ s Time (T): (s) displacement (S): m (m) distance: M Speed unit conversions: 1m/, s=3.6Km/, H Note: (1) the average speed is a vector. (2) the object is very large and the acceleration is not necessarily large. (3) a= (V_t - V_o) / T is just a measure, not a decision. (4) other relevant content: particle / displacement and distance, /s--t diagram, /v--t diagram / velocity and rate 2) free fall 1. initial speed V_o =0 2. end velocity V_t = g t 3. drop height h=gt2 / 2 (down from V_o position) 4. corollary V T2 = 2GH Note: (1) free fall motion is a uniformly accelerated linear motion with zero initial velocity, followed by uniform velocity and linear motion. (2) a=g=9.8 ~ 10m/s2 acceleration of gravity at the equator is smaller in the mountains than plains, vertical direction. 3) vertical projectile 1. T - 2 GT / S=V_o displacement at the end of the 22. speed V_t = V_o - g t (g=9.8 = 10 m / S2) 3. useful inferences V_t 2 - V_o 2 = - 2 g S 4. rise maximum height H_max=V_o 2 / (2G) (throw point count) 5. round-trip time t=2V_o / g (time from the throw back to the original position) Note: (1) the whole process is a uniform deceleration linear motion, in which th
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