第4章 配合物（Fourth chapter complexes）.docVIP

第4章 配合物（Fourth chapter complexes） Fourth chapter complexes 9-1 design some experiments to prove that the yellow of crude hydrochloric acid is the complex ion of Fe3+ and Cl-, not the hydrated ion of iron or the color of hydroxyl ion. 9-2 FeF63- for 6 coordination, and FeCl4- for four coordination, how to explain? 2, solution: fluorine ion small, large chloride ion. 9-3, MA3B3, MA2B4, MABC4, MA2B2C2, MABCDEF (M stands for central atoms, other letters represent ligands), each of them may have several stereoisomers (including geometric isomerism and enantiomeric isomerism) Is there any isomer of 9-4 - and six - coordinate eight - body complexes three (ethylenediamine) copper? 4, Xie: there are 1 pairs of enantiomers. 9-5 why does the hydrolysis product Pt (OH) 2 (NH3) 2 react with oxalic acid to produce Pt (NH3) C2O4, while its geometrical isomer does not? Which isomer has polarity and no polarity? Which kind of water solubility is bigger? 5 solution: the bidentate ligand has a short carbon chain, so it is impossible to match the ligands. The polarity of CIS polarity is large and the water solubility is large. 9-6 coordination chemistry founder Werner found that the amount of substances such as yellow, purple red, green CoCl3.6NH3 CoCl3.5NH3 CoCl3.4NH3 and CoCl3.4NH3 four kinds of purple complexes are soluble in water, adding silver nitrate, immediately precipitated silver chloride were 3, 2, 1, 1mol, please according to the experimental facts to infer the composition with their ion with the. The number of ions ionized in the solution, the magnitude of the ion number and the conductance, and the Cheng Zheng correlation can be determined by the conductance method. What is the quantitative relationship between the conductance ratios of these four complexes? 6, solution: [Co (NH3) 4 (H2O) 2]3+; [Co (NH3) 4 (H2O) Cl]2+; [Co (NH3) 4Cl2]+; [Co (NH3) 4Cl2]+[Co (H2O) 2Cl4]- 9-7, Fe (CN), 64- and Co (NH3) 63+ are diamagnetic substances (magnetic moment equals zero), and their h