在线作业指针作函数参数用法（The online job pointer is used as function parameter）.docVIP

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在线作业指针作函数参数用法（The online job pointer is used as function parameter）.doc

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在线作业指针作函数参数用法（The online job pointer is used as function parameter）

在线作业指针作函数参数用法（The online job pointer is used as function parameter） 9.11 odd or even numbers in an array Results: 100 / Discount: 0.8 Please make up a function fun (int, *a, int, N, *odd, int, *even, int). The function of the function is to find the sum of all odd numbers in the array, and the sum of all even numbers. The parameter n gives the number of data in the array: returns the sum of the odd numbers by using the pointer odd, and returns the sum of the even numbers by the pointer even. For example: the values in the array are: 1, 8, 2, 3, 11, 6, and then use the pointer odd to return the odd numbers and 15; use the pointer even to return the even numbers and 16. Part of the program source code is as follows. #include stdio.h #define N 20 Void, fun (int, *a, int, N, int, *odd, int, *even) {int i; *odd=*even=0; For (i=0; in; i++) If (a[i]%2==0) *even=*even+a[i]; Else *odd=*odd+a[i]; } Int, main () {int, a[N], I, N, odd, even; Scanf (%d, n); For (i=0; in; i++) Scanf (%d, a[i]); Fun (a, N, odd, even); Printf (The, sum, of, numbers:%d\n, odd, odd); Printf (The, sum, of, number:%d\n, even, even); Return 0; } Test input, expected output time limit, memory limit, extra process Test case 1 shows 6 in text mode 1823116? Display The, sum, of, odd, numbers:15 in text mode? The, sum, of, even, number:16? Unlimited 64M 0 9.12 floating points, four, five Results: 100 / Discount: 0.8 Please make a function float fun (double, a, double, *h). The function of the function is to keep 2 decimal places for the value in the variable H, and to do four to five entries for third bits (the value in the H is positive). For example, the H value is 8.32433, and the function returns 8.32; The H value is 8.32533, and the function returns 8.33. Part of the program source code is as follows. #include stdio.h Void fun (double, a, double, *h) {int, B, c; B= (int) (a*1000); C=b%10; If (c=5) b= (b-c+10) /10; If (c5) b=b/10; *h= (float) b/100; } Int, main () { Double, a, h; Scanf (%lf, a); Fun (a,