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汉字编码的编程问题(Programming problems of Chinese characters coding)
汉字编码的编程问题(Programming problems of Chinese characters coding)
Programming problems of Chinese characters coding
Published: qcgxlg read: 95 key words: Chinese character code, interception string, font: [large, medium, small]
//* programming function: write a string, the input is a string and number of bytes,
The output is a string intercepted by bytes. But make sure Chinese characters are not cut off half,
Such as I ABC 4, should be cut as I AB, enter I ABC Han DEF, 6, should be output as I ABC instead of I ABC+ Han half.
* /
Class SplitString
{
Private String str;
Private int byteNum;
Public (SplitString) {}
Public SplitString (String, STR, int, byteNum)
{
This.str=str;
This.byteNum=byteNum;
}
Public, void, splitIt ()
{
Byte, bt[]=str.getBytes ();
System.out.println (Length of this String +bt.length ===);
If (byteNum1)
{
If (bt[byteNum]0)
{
PBinInt (bt[byteNum], bt[byteNum]);
System.out.println (bt[, +byteNum+) = +bt[byteNum]); //1
System.out.println (bt[, +byteNum+) = + (int) bt[byteNum]); //2
系统的输入(“BT [“+ bytenum +”] =“+(BT [ bytenum ]和0x000000ff));/ / 3
系统的输入(“BT [“+ bytenum +”] =“+(BT [ bytenum + 1 ] 0xff));/ / 4
字符串substrx =新的字符串(BT,0,-- bytenum);
系统,println(substrx);
}
其他的
{
字符串substrex =新的字符串(BT,0,bytenum);
系统,println(substrex);
}
}
其他的
{
如果(bytenum = = 1)
{
如果(BT [ bytenum ]<0)
{
字符串substr1 =新的字符串(BT,0,+ + bytenum);
系统,println(substr1);
}
其他的
{
字符串substr2 =新的字符串(BT,0,bytenum);
系统,println(substr2);
}
}
其他的
{
系统。
Out.println (input error!!! Please enter an integer greater than zero: ;
}
}
}
Static, void, pBinInt (String, s, int, I) {
System.out.println (
S +, int: + I +, binary:);
System.out.print ();
For (int = J = 31; J =0; j--)
If ((1, J) I = = 0)
System.out.print (1);
Else
System.out.print (0);
System.out.println ();
}
}
Class TestSplitString
{
Public, static, void, main (String, args[])
{
String str= Im ABCe, DEFe!;
Int num=6;
SplitString sptstr = new SplitString (STR, num);
Sptstr.splitIt ();
}
}
Should the general idea is: each Chinese characters corr
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