高中数学 124切割线定理课件 北师大版选修4-1.pptVIP

ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 4 5 ZHISHI SHULIZHISHI SHULIZHISHI SHULIZHISHI SHULI 知识梳理知识梳理知识梳理知识梳理 ZHONGNAN JVJIAOZHONGNAN JVJIAOZHONGNAN JVJIAOZHONGNAN JVJIAO 重难聚焦重难聚焦重难聚焦重难聚焦 DIANLI TOUXIDIANLI TOUXIDIANLI TOUXIDIANLI TOUXI 典例透析典例透析典例透析典例透析 MUBIAODAOHANGMUBIAODAOHANGMUBIAODAOHANGMUBIAODAOHANG 目标导航目标导航目标导航目标导航 1 2 3 4 5 解:如图所示,延长PO交☉O于点E, 则PA·PE=PB·PC. 设PC=x(x0), ∵PB=BC,∴PB=x. 又PE=PA+AE=PA+2AO=16, ∴2×16=x·x,解得x=±8. 又x0,∴x=8.∴PC=8. 高中数学 124切割线定理课件 北师大版选修4-1教材 谢谢 -*- 2.4　切割线定理 -*- 2.4　切割线定理 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1.理解并掌握切割线定理及推论. 2.理解并掌握切割线定理的逆定理. 3.能够熟练地应用切割线定理及推论解决相关问题. ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 1 2 3 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 ZHISHI SHULI 知识梳理 ZHONGNAN JVJIAO 重难聚焦 SUITANGYANLIAN 随堂演练 DIANLI TOUXI 典例透析 MUBIAODAOHANG 目标导航 题型一 题型二 题型三 题型四 ZHISHI SHULIZHISHI SHULIZHISHI SHULIZHISHI SHULI 知识梳理知识梳理知识梳理知识梳理 ZHONGNAN JVJIAOZHONGNAN JVJIAOZHONGNAN JVJIAOZHONGNAN JVJIAO 重难聚焦重难聚焦重难聚焦重难聚焦 SUITANGYANLIANSUITANGYANLIANSUITANGYANLIANSUITANGYANLIAN 随堂演练随堂演练随堂演练随堂演练 DIANLI TOUXIDIANLI TOUXIDIANLI TOUXIDIANLI TOUXI 典例透析典例透析典例透析典例透析 MUBIAODAOHANGMUBIAODAOHANGMUBIAODAOHANGMUBIAODAOHANG 目标导航目标导航目标导航目标导航 题型一 题型二 题型三 题型四 证明:如图所示,连接BC,BD. ∵E为的中点,∴∠DBE=∠CBE. 又A