关于不等证明方法的探讨毕业论文.docVIP

关于不等式证明方法的探讨对证明方法的学习，可以帮助我们解决一些实际问题，增强对逻辑推理能力、抽象思维和思维能力的培养，并养成善于思考的良好学习习惯。The Discussion about A Lot of Methods about Inequality Proof Abstract: Inequality is a very important high school mathematics content, almost all of the content throughout the entire high school math; people in real life are often applied to some of its knowledge, such as supermarkets, shopping malls stocking the most common design, Inns hotel rental program design, entertainment, consumer purchase program design. However, as we use Inequality Inequality provided strong evidence. Therefore, the discussion of research on inequality proof considerable practical significance. In this article, I summarize the comparative method, analysis and comprehensive method, reductio ad absurdum, scaling law, change element method, the more common method of proof by mathematical induction, parabola method, geometric proofs, monotonic function, extremes and so on. By learning these proven methods that can help us solve some practical problems, the ability to develop logical reasoning and abstract thinking ability and develop diligent in thinking, good at thinking of good study habits . Keywords: inequality; school mathematics; program design; comparative law; geometric proof; function. 前言 不等式的在实际生活中的应用非常广泛,社会生活和生产的各个方面都有应用。这里简单列举一例 进货方案设计型 ? 　　例、商店须进购一些电冰箱和空调机，经过市场调查统计，决定进购电冰箱的数量不得少于空调机的进货量的一半．电冰箱和空调机的进价和售价（元/台）在下面： ? 电冰箱 空调机 进价 800 3500 售价 00 4000 ? 　　计划进购电冰箱和空调机共100台，商店最多可筹集资金311 800元． ? 　　（1）请你帮忙计算有多少种方案进货？? 　　（2）哪种进货方案获利最多？并求出最多利润。（假设商品已全部售出） ? 　　解：（1）设商店进购电冰箱x台，则进购空调机（100－x）台，依题意得：　　　　　 ，那么最少进购电冰箱34台，最多56台，该商可有13种进货方案．????　　（2）设商店总获利为y元，依题意得： y＝（3200－2800）x＋(4000－3500)(100－x)＝—100x＋50000．?????∴　当x最小时，y的值最大．Y|34=46600. ∴ 当x＝34时，商店获利最多,且为46600元 摘要……………………………………………………………………………………1 Abstract………………………………………………………………………………2 前言……………………………………………………………………………………3 1常用证明方法………………………………………………………………………6 1.1 比较法（作差法）……………………………………………………………6 1.1.1 概述………………………………………………………………………6 1.1.2基本分类………………………………………………………………… 6