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本科生毕业设计(论文)
外文翻译
A Discussion on a Limit Theorem and Its Application
Abstract: This paper proposes that a limit theoremcan help to solve a specific limit problemof sum formula and that some limit of product formula can also be solved by exploiting the feature of logarithm function.
Keywords: limit theorem; sumformula; product formula
Incalculus,we will usually solve a specific limit problem of sum formula
But this sum formula can’t sum directly, and it can’t change into some kinds of function’s integral sum. So it is hard to work out its limit , for solve this problem.
This paper’s proposes is that a limit theorem can help to solve this limit problem of sum formula and that some limit of product formula can also be solved by logarithm function.
Theorem1 Let (a) f be differentiable at x=0 and f (0) =0,(b) g be integrable for x∈[a, b].
We have
Proof By the (a), for every thereis a 0 such that implies .
Then by the (b), there exists a real number M0 such that | g(x)| ≤M for x∈[a,b] and there is a 0 such that‖T‖implies
Let ,so when‖T‖δ, we get
and therefore
We note the preceding argument was based on the assumption that f (0) =0. For the case that f (0) ≠0. We can show that
for f (0) 0 and
Let f (x) =x then theorem 1 has become
This is definition of definite integral , and by logarithm function we get
Corollary2 If f be differentiable at x=0 and f (0) =1 and g be integrable for x into [a,b] then we have
In practical is usually divide [0,1] into n parts, and choose (k=1,2, …, n).
Corollary3 Let f be differentiable at x=0 and g be integrable for x into [0,1] , then we have
If f (0) =0, we have
If f(0) =1, we have
Proof By that theorem1 and logarithm function, we get
Example1 Evaluate each of the following:
Solution (a) Rewrite the sum in the equivalent form
So that by theorem1,
(b)Rewrite the sum in the equivalent form
So that by theorem1,
So that by theorem1,
(d)Let f(x) =sinax and g(x) =x. Then
So that by theorem 1,
So that by theorem 1,
Example2
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