盐类水解解析（Hydrolysis analysis of salts）.docVIP

盐类水解解析（Hydrolysis analysis of salts） Analysis of chemical classification in college entrance examination (twelve) -- hydrolysis of salts Interpretation of test sites 1. understand the principle of hydrolysis of salt, grasp the law and application of hydrolysis of salt. 2. understand the acidity and alkalinity of the salt solution. It will compare the concentration of the ion in the salt solution. Questions category (a) multiple-choice questions 1. (in the spring of 2003, 10) is the following several pH indicator color range: pH 3.1~4.4 2 4.4~6.2 3 methyl orange methyl red phenolphthalein 8.2~10, now with 0.1000 mol? L - 1NaOH solution titration close concentration of formic acid, the indicator A. can be used only with B. C. may be used in one or two D. 2. (2002 National Science, 10) at room temperature, the mixture of formic acid and sodium hydroxide solution, the solution pH=7, the solution A.c (HCOO), C (Na +) (B.c HCOO) C (Na +) C.c (HCOO) =c (Na +) D. C (HCOO) cannot be determined with C (Na +) relationship 3. (in the spring of 2001, 18) in the 0.1 mol? L-1 Na2CO3 solution, the following relationship is correct A.c (Na +) = 2C (CO) B.c (OH -) = 2C (H +) C.c (HCO), C (H2CO3) D.c (Na +) C (CO) C (HCO) 4. (2001 Shanghai, 19) 0.1 mol? L-1 sodium acetate solution of 20 mL and 0.1 mol? L-1 HCl 10 mL after mixing, the solution is acidic, the particle concentration relationship in solution is correct A.c (CH3COO) C (Cl -), C (H +), C (CH3COOH) B.c (CH3COO) C (Cl -), C (CH3COOH), C (H) C.c (CH3COO) = C (Cl -), C (H +), C (CH3COOH) D.c (Na +) C (H +) = C (CH3COO) C (CL) C (OH -) (2000 5. national, 10) at room temperature, pH = 12 in a solution of water by ionization of C (OH -) for A.1.0 * 10 - 7 mol? L-1 B.1.0 * 10-6 mol? L-1 C.1.0 * 10-2 mol? L-1 D.1.0 * 10-12 mol? L-1 6. (in the spring of 2000, 5) 0.1 mol? L-1 Na2CO3 and 0.1 mol? L-1 NaHCO3 solution pH, size of the relationship before and after the two volume for A. is greater than B. equals C. is less than D. is n