身份证号码的验证（Verification of ID number）.docVIP

身份证号码的验证（Verification of ID number） In the software development, if it involves the ID card number, it is often necessary to verify the identity card code. At present, our citizenship cards are two generation ID cards, and their numbers are eighteen. The eighteen digit in the top six for the area code, said the members of the native place, eight followed by the civil code and the next birthday, three for police serial number, the odd among male citizens, even to the female citizens. The last bit is the end identifier, which identifies the first seventeen digits. The ID number of the top seventeen respectively (7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2) for the corresponding multiplication, the sum of each product, divided by 11 to take the remainder, the remainder is 0 10, at the end of the corresponding identification codes were:1,0,X,9,8,7,6,5,4,3,2, where X is 10, the ID number are limited to a length of 18, if 10, then broke the ID code length 18 limit, therefore, the Rome digital X said 10. Specific implementation methods can refer to the following C language code. Char passID (char *); Int strtonum (char *); Char dateyn (char *); Void, main () { Char i; Char info[][7]={error, not recognized, normal}; Char ID[]= 510108050229502 / / to use this number to test; Char id[19]; Memcpy (ID, ID, sizeof (ID)); I=passID (ID); Printf (%s, %s, %s\n, Id, ID, info[i+1]); WaitKey (); } Char passID (char *ID) / / determine the parameters provided by the identity card number is correct, if the number 15 and the number is correct, the 18 digit number corresponding to the write pointer parameters {// returns 0 number, 1 right, -1 error, -2 ID code Char id[19]; Char score[]={7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2}; / / check code Char str[]={1,0,X,9,8,7,6,5,4,3,2}; / / end code Char I; / / loop variable Int k; / / check value Char city[7], birthday[9], end[4]; / / area code, code code at the end of the birthday. If (strlen (ID) ==0 return 0); / / does not pr