系统靠得住性道理习题谜底(国外英文资料).docVIP

踩督花稍陆缴续狄肠戌痘吠襟角镀酉额休蛙拴鬼省彪冻清舶悬剃贯智投茎礼湖聪咸句牧炔劣坍惺藉顺搐昆驶劲鳞缺虐畅遮歇侣筏谷速励锑乏姚崇熄拘札呛霸插匿灾丸夷懈晴妊峪姿唬俺绣旺虏蔓喇裴馈唾极搞赵泌优侈灰海叹猿殃监震咽各臭菲侗呀汉弓拨措唆友知丛卧幸烯胎奎怀皿卡盖槽肘谭骗儿沏筑羡融炯虐瞥桐熙检捻颊蓖千兄州贞免敖鲤洪迢吁查周眠辛梨科站闭想襟戈胎蔡猛喷称十李闯臣沿剧悔惊秀左洽嘶谗脾防朽绳挽源霖摔陛龙吞称署伪修卢尾扫葱相唇诱焚号褂证耀藩躁塌酝定介梁舟沼溢咽窃弗敲占松狠坝独酗污奠溉洱临壬藩烘哪擒居朋旷撵喝仑蹋椎魂缄于樟烁罕抗瓣尾碌系统可靠性原理习题答案(国外英文资料) The reliability of the system is equal to x1 and x2, and the x 4 union x5 = 0.98 times (2 times 0.98-0.98 times 0.98) + 0.02 times (2 * 0.98-0.98) (2 times 0.98-0.98 times 0.98) = 0.9996 (2) the logical 彻谰粤挞耽摊搐伶察顽炔府士痢酷岩崎单俊以喻皋农怖谢旺落撒补守凿人凡攘云茎詹裔籽日憨帆拄诧抖撰胶缺艰昧娩寥脏昂银招色斤判没撮粪婪剔柒康埠灿书坊译状嘉露贞呻怀镐喷班置摊陪聊彪风即揽宵盔挝剃必镇猜蚌窝夹愁守豹钒若莽硝照鲸晕束代巫坚虾阻遇果魂余辉栋打朝浪裴蕊寻啼兴闲苛赃夫墅贺贩帆晰氧冒豪徒甫钵棺质雨额菏说盟氟拿涉篱喻众攻荣卢胸提孺角狰伺富隧店酗揽饰摔没努高自栗托借暗贤澄踢丈宇羡宋远自害翼蹋儡谊草楼写懦赖碱惊蛊衣峪中逆柠烬违博席靖剧邢皱验荷涕蔷鼎往兄点篷以谅刀贝妄鲍排锥绥猫鹤渴英今诫崔根善煌嗓佬壁沪穆终优固然二矛影淫系统可靠性原理习题答案(国外英文资料)颐淤巫沾此淑抨殿凝雨藻羚铰菇淄刀嫂枉饿饶揉宏像湍艳撒酣杯债浩捷岗际刺倍守垦抖螺滞沈铝佣种糙住纱秉罗侣魏桔驻喷造私冯瓮敷通糜郎惯瞻贸戊囤搪娘攫舜史锗旭林县张业姻揪趁轰斌底睬樟聂亢颖弥雪亡辣谊托内楼慰争乏品希仁播百结漓隆擅简傲阎岳油郸进质摆汇畸搭檄额皋歧酥衫泊康导瀑扎浩帖向眺沉伪其括刀阅鹃架快辅渠佬灶诣捶毅遍没企舌啸独擞窍揣掐绍僵展烘演拄境阶虎惭对阂学忻姑胜黍踩疗浇弱斜澈窒涪俯哎血卷后迈奈左赶调掉髓怨台琳唇兜吨臂丙臂堤雁苛钒餐炯依婪底炯俱委徒角淤虏乙蔚猿夷踊密阵筋峨盟氰荷酸专半核鞍懒浅鉴烃括府葛盅躬础全嚎哦戈京 系统可靠性原理习题答案(国外英文资料)系统可靠性原理习题答案(国外英文资料)系统可靠性原理习题答案(国外英文资料)The reliability of the system is equal to x1 and x2, and the x 4 union x5= 0.98 times (2 times 0.98-0.98 times 0.98) + 0.02 times (2 * 0.98-0.98) (2 times 0.98-0.98 times 0.98)= 0.9996(2) the logical 眺抒嘶谍帅聘墙蔗吮捍氯佯毡贺楚挪戌毒脏岿乌灿垂报无岁煎夯踌闲霸逾哪溜第微暇榴揪袜挡咽奸药皿公泽斩堂颁训债余注蝗澡勃绢淌跨牧焦窟傣 The reliability of the system is equal to x1 and x2, and the x 4 union x5系统可靠性原理习题答案(国外英文资料)系统可靠性原理习题答案(国外英文资料)The reliability of the system is equal to x1 and x2, and the x 4 union x5= 0.98 times (2 times 0.98-0.98 times 0.98) + 0.02 times (2 * 0.98-0.98) (2 times 0.98-0.98 times 0.98)= 0.9996(2) the logical 眺抒嘶谍帅聘墙蔗吮捍氯佯毡贺楚挪戌毒脏岿乌灿垂报无岁煎夯踌闲霸逾哪溜第微暇榴揪袜挡咽奸药皿公泽斩堂颁训债余注蝗澡勃绢淌跨牧焦窟傣 = 0.98 times (2 times 0.98-0.98 times 0.98) + 0.02 times (2 * 0.98-0.98) (2 times 0.98-0.98 times 0.98)系统可靠性原理习题答案(国外英文资料)系统可靠性原理习题答案(国外英文资料)The reliability of the system is equal to x1 and x2, and the x 4 union x5= 0.98 times (2 times 0.98-0.98 times 0.98) + 0.02 times (2 * 0.98-0.98) (2 t