[2017年整理]化工热力学习题.ppt

已知SO2在431K时第二、第三维理系数分别为 （1）容积为10m3 的钢瓶装有温度和压力分别为431K和4×105Pa 的SO2气体。试计算钢瓶中SO2质量。 （2）在封闭系统内，将1kmol SO2在431K条件下由10×105 Pa 恒温可逆压缩到75×105 Pa。计算该过程所作的功。 Problem Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. （1）因为 p1.5 MPa，选择用二项Virial EoS 求解。 Solution: Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 因为P 1.5 MPa，选择用三项Virial EoS 求解。 (D) （2） Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 用迭代法由Eq D 解出V1 和 V2，代入Eq E，求出功。 (E) Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Example 用普遍化方法计算 510 K、2.5 MPa 时正丁烷的气相摩尔体积。已知实验值为 1.4807 m3 / kmol。 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Solution 查附录得到正丁烷的临界参数和偏心因子： pc = 3.80 Mpa， Tc = 425.2 K， ω = 0.193 计算正丁烷的对比态参数 因为 应该应用Pitzer普遍化第二Virial系数法进行计算。 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 将计算值同实验值进行比较，查对误差为 如果不应用Pitzer普遍化第二Virial系数法，而是选择Pitzer普遍化压缩因子图法，计算结果为： 查图2-7，得到Z0 = 0.83；查图2-8，得到Z1 = 0.038 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 试求CO2(1)-C3H8(2)体系在311K和1.5MPa的条件下的混合物摩尔体积，两组元的摩尔比为3:7(二元交互作用参数kij近似取为0)。 ij Tcij/K Pcij/Mpa Vcij/m3·kmol-1 Zcij ωij 11 304.2 7.382 0.0940 0.274 0.228 22 369.8 4.248 0.2000 0.277 0.152 12 335.4 5.472 0.1404 0.2755 0.190 首先根据附录三查得两种纯组元的临界参数，根据式 (2-53a)~(2-53e)计算混合物的交互临界参数 Example 2-10 Solution Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 计算混合物的交互第二维里系数，计