thinkinginjava学习笔记1-全面解读方法重载.docxVIP

thinking in java学习笔记1——全面解读方法重载 分类： java 2011-11-06 21:44 92人阅读 评论(1) 收藏 举报 之前学习C++时对于方法重载有了一点认识，最近看了java编程思想一书，对书中方法重载的章节进行了一番研习发现之前对于方法重载的认识很浅薄很片面，所以在此总结下最近关于方法重载的学习结果，希望能比较全面的解读下方法重载。 一，方法重载的基本认识： 学习之前我们需要了解什么是方法重载，方法名相同而参数不同的方法既是方法重载，简单而言就是让类以统一的方式处理不同类型数据的一种方法。举个例子就能直观的看出来了，例如：void show() {……}；void show(String s) {……}，例中定义了名字同为show的两个方法，可以看出他们的参数不同，这即为方法重载。 那么方法重载有什么作用呢？前面我们已经解读过构造器，有时程序中需要用到参数不同而方法名相同的构造器，如果直接定义那么就会产生错误，此时方法重载就发挥了很大的作用，计算机可以通过方法重载中传递的参数找到适合的构造器进行调用，从而实现功能。 下面给出个简单的例子加深下认识。 [java] view plaincopyprint?class Tree { int height; Tree() { prt(Planting a seedling); height = 0; } Tree(int i) { prt(Creating new Tree that is + i + feet tall); height = i; } void info() { prt(Tree is + height + feet tall); } void info(String s) { prt(s + : Tree is + height + feet tall); } static void prt(String s) { System.out.println(s); } } public class Overloading { public static void main(String[] args) { for(int i = 0; i 5; i++) { Tree t = new Tree(i); t.info(); t.info(overloaded method); } // Overloaded constructor: new Tree(); } } /*Output: Creating new Tree that is 0 feet tall Tree is 0 feet tall Overloading method: Tree is 0 feet tall Creating new Tree that is 1 feet tall Tree is 1 feet tall Overloading method: Tree is 1 feet tall Creating new Tree that is 2 feet tall Tree is 2 feet tall Overloading method: Tree is 2 feet tall Creating new Tree that is 3 feet tall Tree is 3 feet tall Overloading method: Tree is 3 feet tall Creating new Tree that is 4 feet tall Tree is 4 feet tall Overloading method: Tree is 4 feet tall Planting a seeding*/ class Tree { int height; Tree() { prt(Planting a seedling); height = 0; } Tree(int i) { prt(Creating new Tree that is + i + feet tall); height = i; } void info() { prt(Tree is + height + feet tall); } void info(String s) { prt(s + : Tree is + height + feet tall); } static void prt(String s) { System.out.println(s); } } public