宁夏银川市第九中学高中数学人教A版必须修读一演示课件-1-2函数的概念习题课.pptVIP

Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 1.已知 集合A＝{x | f (x)＝x且x＋m≠0}， B＝{x | f (x＋6)＋x＝0}， 若A＝{3}，求集合B. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 2.函数r＝f (p)的图象如下图所示. (1)函数r＝f (p)的定义域可能是什么？ (2)函数r＝f (p)的值域可能是什么？ (3)r的哪些值只与p的一个值对应？ r O 5 2 -5 p 2 6 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 3.画出定义域为{x| –3≤x≤8, 且x≠5}， 值域为{y | –1≤y≤2，y≠0}的一个函 数的图象. (1)如果平面直角坐标系中点P (x, y)的 坐标满足–3≤x≤8，–1≤y≤2，那么 其中哪些点不能在图象上？ (2)将你的图象和其他同学的相比较， 有什么差别吗？ Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 4.已知函数f (x)对任意的实数a，b都 有f (a·b)＝f (a)＋f (b)成立. (1)求f (0)与f (1)的值； (2)若f (2)＝p，f (3)＝q (p，q均为常 数)，求f (36)的值. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 5.设f (x)是定义在实数集R上的函数， 满足f (0)＝1且对任意实数a，b都有 f (a)－f (a－b)＝b (2a－b＋1)，则 f (x)的解析式可以为 ( A ) A．f (x)＝x2＋x＋1 B．f (x)＝x2＋2x＋1 C．f (x)＝x2－x＋1 D．f (x)＝x2－2x＋1 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 5.设f (x)是定义在实数集R上的函数， 满足f (0)＝1且对任意实数a，b都有 f (a)－f (a－b)＝b (2a－b＋1)，则 f (x)的解析式可以为 ( A ) A．f (x)＝x2＋x＋1 B．f (x)＝x2＋2x＋1 C．f (x)＝x2－x＋1 D．f (x)＝x2－2x＋1 Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 6.如图，矩形的面积为10. 如果矩形的 长为x，宽为y，对角线为d，周长为l， 那么你能获得关于这些量的哪些函数？ d y x Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 7.一个圆柱形容器的底部直径是dcm， 高是hcm. 现在以vcm3/s的速度向容 器内注入某种溶液. 求容器内溶液的 高度xcm与注入溶液的时间ts之间的 函数解析式，并写出函数的定义域 和值域. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. 8.如图所示，一座小岛距离海岸线上最 近的点P的距