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与加速度有关公式(Formula relating to acceleration)
与加速度有关公式(Formula relating to acceleration) Education / Science know the problem has been resolved page related to acceleration and Acceleration Formula for the high school is all about the formula hao508506? 2008-10-21 the best answer physical theorem and law, formula table First, the motion of the particle (1) - linear motion 1) uniform variable rectilinear motion The average speed of 1. V = s/t (definition 2.) useful corollary Vt2-Vo2 = 2As 3. middle time speed Vt/2 = V = /2 flat (Vt+Vo) at the end of the 4. speed Vt = Vo+at 5. intermediate position velocity Vs/2 = [(Vo2+Vt2) /2]1/2 s V t 6. displacement = = Vot+at2/2 = Vt/2t 7. acceleration a (Vt-Vo) /t = {Vo is a and Vo to the same direction, a0 (acceleration); reverse a0} The 8. corollary is s = aT2 {Delta s for continuous time (T) adjacent equal displacement difference} 9. main physical quantities and units: the initial velocity (Vo): m/s (A: m/s2); acceleration; terminal velocity (Vt): m/s (T); time (s seconds); displacement (s): m (m); distance: meters; speed conversion: 1m/s=3.6km/h. Note: (1) the average velocity is a vector; (2) the object velocity, acceleration is not large; (3) a= (Vt-Vo) /t is measured, not to; (4) other related content: the particle displacement and distance, reference system, time and moment to see the first volume of P19 /s--t and v--t charts / speed and rate, the instantaneous speed, see the first volume P24. 2) free fall 1. the initial velocity of Vo = 2 at the end of the speed Vt = GT 3. H = gt2/2 (drop height from Vo down position calculation) 4. that Vt2 = 2GH Note: (1) the free fall is zero initial velocity uniformly accelerated linear motion, follow the linear motion law of uniform transmission; (2) a = g = 9.8m/s2 = 10m/s2 (the acceleration of gravity at the equator is smaller in the mountains than plains, vertical direction). (3) vertical projectile motion 1. s = 2. Vot-gt2/2 displacement speed Vt = Vo-gt (g=9.8m/s2 = 10m/s2) 3. useful corollary Vt2-Vo2 = -2gs 4. Hm maxim
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