Sect 2.6 Formulas and Applications of Geometry（教派2.6几何的公式和应用）.pdfVIP

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Sect 2.6 Formulas and Applications of Geometry（教派2.6几何的公式和应用）.pdf

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Sect 2.6 Formulas and Applications of Geometry（教派2.6几何的公式和应用）

72 Sect 2.6 - Formulas and Applications of Geometry: Concept #1 Solving Literal Equations for a particular variable. Now, we will examine solving formulas for a particular variable. Sometimes it is useful to take a formula that is solved for one variable and rewrite it so it is solved for another variable. To see how this is done, we will first work a problem with numbers that we can plug in and solve. We will then use that as a blueprint for solving a formula (or literal equation) for a particular variable. Solve: Ex. 1a A = Lw (area of a rectangle); A = 45 ft2 and w = 9 ft Solution: Substitute the given values for A and w and solve: A = Lw 45 = L(9) (rewrite the right side) 45 = 9L (divide both sides by the number in front of L) 9 9 5 = L So, L = 5 ft. Ex. 1b A = Lw for L Solution: Follow the steps we performed in Ex. 1a after substituting: A = Lw (rewrite the right side) A = wL (divide both sides by the number in front of L) w w A A = L So, L = . w w Ex. 2a i = prt (simple interest); r = 0.09, t = 1.5 i = $945 Solution: Substitute the given values and solve: i = prt 945 = p(0.09)(1.5) (multiply) 945 = 0.135p (divide by the number in front of p) 0.135 0.135 7000 = p So, p = $7000