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java转义字符(Java escape character)
java转义字符(Java escape character) Escape the escape character in 17:40JAVA 2009-08-12 characters in JAVA: The 1. octal escape sequence: \ + 1 to 3 5 numbers;\000~\377 \0: empty character 2.Unicode escape character: \u + four sixteen hexadecimal numbers; 0~65535 \u0000: empty character 3. special characters: 3 Double quotes: single quotes: A backslash \ \: 4. control characters: 5 singlequotedcharacter The backslash character \ \ Enter \r \n wrap \f paper page \t horizontal jump \b backspace The escape: == u002E. The dollar sign: $== u0024 The escape symbol: u005E ^ == involution Escape left brace: {== u007B Escape the left bracket: == [u005B The left parenthesis: == (u0028 A: | == escape u007C Escape right parenthesis: ==) u0029 An asterisk * == escape: u002A Plus: u002B + == escape Mark: u003F == escape? Escape backslash: == u005C ====================================================================== The following program uses two Unicode escape character, they are used to represent the Unicode character hexadecimal code sixteen. So, what will the program print? Java code Public class EscapeRout{ Public static void main (String[] args) { / / \u0022 is a Unicode escape double quotes System.out.println (a\u0022.length () +\u0022b (.Length)); } } Public class EscapeRout{ Public static void main (String[] args) { / / \u0022 is a Unicode escape double quotes System.out.println (a\u0022.length () +\u0022b (.Length)); } } On a very superficial analysis of the program will think it should print out the 26, because in the two double quotes (a\u0022.length) a total of 26 characters between the string +\u0022b logo. A little further analysis point that the program should print 16, because the two Unicode escape character in each source file need to use 6 characters to say, but they only said a character in a string. Therefore, this should be the shorter string of 10 characters than it looks. If you run this program, you will find things are not so. This print is neither 26 nor
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