通过ajax.dll实现ajax的开发（Implementation of AJAX development through ajax.dll）.docVIP

通过ajax.dll实现ajax的开发（Implementation of AJAX development through ajax.dll） The content of this page is: through the ajax.dll to achieve the development of Ajax, the article reprinted from the network site, if there is infringement, please inform, we will promptly delete it, the text reads as follows: The recent upsurge of Asynchronous JavaScript and XML (AJAX) is entirely due to the use of Google in Google, Suggest, and Google Maps. For ASP.NET, AJAX does not require backhaul to do server-side processing, thus enabling clients (browsers) to have rich server-side capabilities. In other words, it provides a framework for asynchronous assignment and processing of requests and server responses. AJAX has taken advantage of some of the techniques that are not very novel, but the interest in these technologies (together with AJAX) has recently been heating up. Try Michael Schwarzs AJAX.NET wrapper through which ASP.NET developers can quickly and easily deploy pages that make it easy to use AJAX functionality. It should be noted that this wrapper is in its early stages of development and is therefore not yet fully fledged. How it works - an overview AJAX relies on the agent (broker) to assign and handle requests from the round trip server. In this case, the.NET wrapper relies on the client XmlHttpRequest object. Most browsers support XmlHttpRequest objects, which is why they choose it. Since the wrappers purpose is to hide the implementation of XmlHttpRequest, we will not discuss it in detail. The wrapper itself works by marking the.NET function as the AJAX method. After the tag, AJAX creates the corresponding JavaScript function, which, like any JavaScript function, acts as an agent and can use XmlHttpRequest calls on the client side. These proxies are mapped back to server-side functions. Is it complicated? Not complicated. Lets look at an example. Suppose there is a.NET function: Ublic, int, Add (int, firstNumber, int, secondNumber) { Return firstNumber + secondNumber; } T