备战中考初中数学全部重点公式(For all of the key senior high school entrance examination of junior high school mathematics formula).docVIP
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备战中考初中数学全部重点公式(For all of the key senior high school entrance examination of junior high school mathematics formula)
备战中考初中数学全部重点公式(For all of the key senior high school entrance examination of junior high school mathematics formula) Multiplication and factor a2-b2= (a+b) (a-b) a3+b3= (a+b) (a2-ab+b2) a3-b3= (a-b (a2+ab+b2) The triangle inequality is less than or equal to |a|+|b| less than or equal to |a|+|b| |a-b| |a+b| |a| = b=-b = a = b |a-b| = |a|-|b| -|a| = a = |a| -b+ have the solutions of quadratic equation with one unknown of the (b2-4ac) /2a -b- (b2-4ac) /2a V The root and coefficient of relationship between X1+X2=-b/a X1*X2=c/a note: Viete theorem Discriminant Note: the b2-4ac=0 equation has real roots of two equal Note: the b2-4ac0 equation has two different real roots Note: the b2-4ac0 equation has no real roots, there are complex conjugate roots Trigonometric function The horns and formula Sin (A+B) =sinAcosB+cosAsinB sin (A-B) =sinAcosB-sinBcosA Cos (A+B) =cosAcosB-sinAsinB cos (A-B) =cosAcosB+sinAsinB Tan (A+B) = (tanA+tanB) / (1-tanAtanB) Tan (A-B) = (tanA-tanB) / (1+tanAtanB) CTG (A+B) = (ctgActgB-1) / (ctgB+ctgA) CTG (A-B) = (ctgActgB+1) / (ctgB-ctgA) Double angle formula Tan2A=2tanA/ (1-tan2A) ctg2A= (ctg2A-1) /2ctga Cos2a=cos2a-sin2a=2cos2a-1=1-2sin2a Half angle formula Sin (A/2) = V ((1-cosA) /2) sin (A/2) = V ((1-cosA) /2) Cos (A/2) = V ((1+cosA) /2) cos (A/2) = V ((1+cosA) /2) Tan (A/2) = V ((1-cosA) / ((1+cosA)) Tan (A/2) = V ((1-cosA) / ((1+cosA)) CTG (A/2) = V ((1+cosA) / ((1-cosA)) CTG (A/2) = V ((1+cosA) / ((1-cosA)) And the difference of product 2sinAcosB=sin (A+B) +sin (A-B) 2cosAsinB=sin (A+B) -sin (A-B) 2cosAcosB=cos (A+B) -sin (A-B) -2sinAsinB=cos (A+B) -cos (A-B) SinA+sinB=2sin ((A+B) /2 (/2) cos (A-B) cosA+cosB=2cos ((A+B) /2 (/2) sin (A-B)) TanA+tanB=sin (A+B) /cosAcosB tanA-tanB=sin (A-B) /cosAcosB CtgA+ctgBsin (A+B) /sinAsinB -ctgA+ctgBsin (A+B) /sinAsinB Some n series before and 1+2+3+4+5+6+7+8+9+... +n=n (n+1) /2 1+3+5+7+9+11+13+15+... (2n-1 + =n2) 2+4+6+8+10+12+14+... (2n) + =n (n+1) 12+22+32+42+52+62+72+82+... +n2=n (n+1) (2n+1) /6 13+23+3
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