c语言学生平均分(C language students average).docVIP

c语言学生平均分(C language students average).doc

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c语言学生平均分(C language students average)

c语言学生平均分(C language students average) If (min==a[i].s) B[j++]=a[i]; / * find scores and min equal to the students record, structure into B. Return j; } 10. put below average into B, the number is returned by the parameter N, and is returned by the function value Double fun (STREC, *a, STREC, *b, int, *n) { Int, I, j=0; Double ave=0.0; For (i=0; iN; i++) Ave=ave+a[i].s; Ave=ave/N; / * * / average For (i=0; iN; i++) If (a[i].save) b[j++]=a[i]; / * will be lower than the average value of the student records stored in the structure of B. *n=j; / * pointer returns is lower than the average number of students. Return ave; / * * / return average } 11.fun: set the score range into B, and the number of people returned Int, fun (STREC, *a, STREC, *b, int, l, int, H) { Int, I, j=0; For (i=0; iN; i++) If (a[i].s=la[i].s=h) The score is higher than that of L / h, lower than the student records stored in an array of structures in B. B[j++]=a[i]; Return J; / * returns the scores within the scope of the number of students. } 12.fun: finds the highest record of students, returns the main function through the parameter and has only one maximum. Fun (STU, a[], STU, *s) { Int i; *s=a[0]; For (i=0; iN; i++) / * find the highest score / student records If (s-sa[i].s) *s=a[i]; } 13. find the lowest score of the student record and return the primary function through the parameter. There is only one, Fun (STU, a[], STU, *s) { Int i; *s=a[0]; / * * / first minimum first think For (i=0; iN; i++) / * if in the process of the circulation of more than first small values found are assigned to *s*/ If (s-sa[i].s) *s=a[i]; } In score, 14.m scores are returned as function values, and scores are placed in below Int fun (int, score[], int, m, int, below[]) { Int, I, j=0; Float av=0.0; For (i=0; im; i++) Av=av+score[i]/m; / * * / average For (i=0; im; i++) If (score[i]av) / * if the score is lower than the average score, the scores in the below array. Below[j++]=score[i]; Return J; / * returns below th

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