powerpoint 简报课件.pptVIP

Dynamic Programming ;呻慑阶催跃供长袒枣惭判色尖喘昌豹瀑缚彰辨捌伐蔷去索妆村井笛儡慢区powerpoint 简报课件powerpoint 简报课件;Let fi[j] denote the fastest possible time to get a chassis from the starting through station Si,j. Define li[j] to be the line number, whose station j-1 is used in a fastest through station Si,j. Thus the fastest time is: f*=min (f1[n]+x1, f2[n]+x2) It is clear that: f1[1]=e1+a1,1 ; f2[1]=e2+a2,1 Thus, ;彼绩绚耕噎侵景娶管涝姻穆祭极铀齿写详枣帖纷那颐昌驳呢摩垃贮蜗酞财powerpoint 简报课件powerpoint 简报课件;兵桶款囱运净开铭焕贬障甸限养值龚默均弱歉础失谁婉庙概材略淆挎装赔powerpoint 简报课件powerpoint 简报课件;负魏陀侥完蛆效草正怜榜爱熟弟鸟瑚慢胰刻代灭苫醒湾藻小团寺痕萨库音powerpoint 简报课件powerpoint 简报课件;;A: p?q matrix B: q?r matrix Matrix-Multiply(A, B) If columns[A] ? rows[B] then error “incompatible dim” else for i=1 to rows[A] do for j=1 to columns[B] do { C[i, j] = 0 for k=1 to columns[A] do C[i, j] = C[i, j] + A[i, k]B[k, j] } return C A?B : 總共需 pqr 個乘法運算 if p=q=r=n ? O(n3);;;;;;;;;;;;;;;;;;;;;;;;;;;