Area Moment of inertia The University of Sydney（区域惯性矩悉尼大学）.docVIP

下载本文档

14
0
约2.48千字
约 9页
2017-08-11 发布于浙江
举报
版权申诉

Area Moment of inertia The University of Sydney（区域惯性矩悉尼大学）.doc

1、有哪些信誉好的足球投注网站（book118）网站文档一经付费（服务费），不意味着购买了该文档的版权，仅供个人/单位学习、研究之用，不得用于商业用途，未经授权，严禁复制、发行、汇编、翻译或者网络传播等，侵权必究。。
2、本站所有内容均由合作方或网友上传，本站不对文档的完整性、权威性及其观点立场正确性做任何保证或承诺！文档内容仅供研究参考，付费前请自行鉴别。如您付费，意味着您自己接受本站规则且自行承担风险，本站不退款、不进行额外附加服务；查看《如何避免下载的几个坑》。如果您已付费下载过本站文档，您可以点击这里二次下载。
3、如文档侵犯商业秘密、侵犯著作权、侵犯人身权等，请点击“版权申诉”（推荐），也可以打举报电话：400-050-0827(电话支持时间：9:00-18:30)。
4、该文档为VIP文档，如果想要下载，成为VIP会员后，下载免费。
5、成为VIP后，下载本文档将扣除1次下载权益。下载后，不支持退款、换文档。如有疑问请联系我们。
6、成为VIP后，您将拥有八大权益，权益包括：VIP文档下载权益、阅读免打扰、文档格式转换、高级专利检索、专属身份标志、高级客服、多端互通、版权登记。
7、VIP文档为合作方或网友上传，每下载1次，网站将根据用户上传文档的质量评分、类型等，对文档贡献者给予高额补贴、流量扶持。如果你也想贡献VIP文档。上传文档

Area Moment of inertia The University of Sydney（区域惯性矩悉尼大学）

Area Moment of inertia The area moment of inertia is the second moment of area around a given axis. For example, given the axis O-O and the shaded area shown, one calculates the second moment of the area by adding together for all the elements of area dA in the shaded area. The area moment of inertia, denoted by I, can, therefore, be calculated from ? If we have a rectangular coordinate system as shown, one can define the area moment of inertial around the x-axis, denoted by Ix, and the area moment of inertia about the y-axis, denoted by Iy. These are given by ? The polar area moment of inertia, denoted by JO, is the area moment of inertia about the z-axis given by ? Note that since one has the relation ? ? The radius of gyration is the distance k away from the axis that all the area can be concentrated to result in the same moment of inertia. That is, ? ? For a given area, one can define the radius of gyration around the x-axis, denoted by kx, the radius of gyration around the y-axis, denoted by ky, and the radius of gyration around the z-axis, denoted by kO. These are calculated from the relations ? ? It can easily to show from that ? ? ? The parallel axis theorem is a relation between the moment of inertia about an axis passing through the centroid and the moment of inertia about any parallel axis. Note that from the picture we have Since gives the distance of the centroid above the x-axis, and since the this distance is zero, one must conclude that the integral in the last term is zero so that the parallel axis theorem states that ? where x must pass through the centroid of the area. In this same way, one can show that ? ? In general, one can use the parallel axis theorem for any two parallel axes as long as one passes through the centroid. As shown in the picture, this is written as ? ? where is the moment of inertia about the axis O-O passing through the centroid, I is the moment of inertia about the axis O-O, and d is the perpendicular distance between th