核辐射探测习题解答6(外国英语资料).docVIP

核辐射探测习题解答6(国外英语资料) This article is contributed by bright_chou DOC documents may experience poor browsing on the WAP side. It is recommended that you first select TXT, or download the source file to the local view. Chapter 1 answer 1. The Po radiation source emits alpha particles (E = 5.304 MeV) in the water range. Answer: first, the alpha particle in the air range, 1 R0 = 0.318E alpha,.5 = 0.318 * 5.3041.5 = 3.88cm Two hundred and ten from P A R1 P = 0 R0 1 A0 A = sigma Ni Ai I A compound or mixture of a variety of elements, since the chemical bond energy between atoms is negligible when compared to the energy of the incident particle In the formula, Ni is the percentage of atoms of each element. For the air, A0 = 3.81, in standard condition, P 0 = 1.226 x 10? 3 G? Cm? 3, so R = 3.2 x 10 A 4? P R0 The range of water in water A = sigma Ni, Ai = I 21 1+ 16 = 233 R = 3.2 * 10 = 4 Z2 = alpha 2 V alpha A 2. it is known that the ionization loss rate of 1 MeV protons in a medium is A, and the ionization loss rate of alpha particles of the same energy is calculated. Answer: so 3. try to answer: 4. calculate answer: One hundred and thirty-seven One hundred and thirty-seven P R0 = 3.2 x 10, 4 x 2 x 3.88 = 24.8 M Z2 MP P Ep 4 x 41 x 1 = 161 S, ion, alpha, S, ion, P Z2 = M = Alpha, E, alpha, V2, P, Z2, P, S, ion., alpha = 16 A = Cs E gamma = 662 KeV gamma ray occurs when the Compton effect is the maximum energy of the recoil electron. Ee, max = V = 0.662 H = 0.478MeV 21 + M0 C 2H v 1 + 0.5112 * 0.662 The cross section of atomic absorption and photoelectron energy of Cs, Fe and Al by Pb gamma ray. What do you get out of it? The Enlightenment of regularity? The known epsilon K are 88.001KeV, 7.111KeV, and 1.559KeV, respectively. One hundred and thirty-seven The gamma ray energy Cs h v = 0.662 MeV, Four 55, 1, 255 sigma pH = Sigma K = x 32 x x x 6.625 x 10 x Z = 1.33 = 10 * 32 Z 5 cm 2 pair Pb, Z = 82, epsilon K = 88.001KeV. 44137 Sigma pH = 1.33 * 10, 32 * (82), 5 = 4.93 * 10, 23