C语言题库1(国外英语资料).docVIP

C语言题库1(国外英语资料) //1, known: Sn=2/1+3/2+4/3+... + (n+1) /n, which asks Sn not to exceed the maximum value of 50 (third to four after five decimal places) #include stdio.h Void, main () { Int n=1; Float s=0; While (s=50) {s=s+ (n+1) *1.0/n; N++;} Printf (%.3f, s-n*1.0/ (n-1)); } //2, known S1=2, S2=2+4, S3=2+4+6, S4=2+4+6+8, S5=2+4+6+8+10,... Seek S=S1+S2+S3+S4+S5+... Value of +S20. #include stdio.h Void, main () { Int, I, t=0; Int s=0; For (i=1; i=20; i++) {t=t+2*i; S=s+t; } Printf (%d, s); } //3, set S=1+1/2+1/3+... 1/n, n is a positive integer, the S does not exceed 10 (S = 10) of the largest n. #include stdio.h Void, main () { Int n=1; Float s=0; While (s=10) {s=s+1.0/n; N++; } Printf (%d, n-2); } //4, set S (n) =1-1/3+1/5-1/7+... 1/ (2n-1), for the value of S (100), requires S (100) to press four Five into the way, accurate to 4 decimal places. #include stdio.h Void, main () { Int i; Float s=0; For (i=1; i=100; i++) If (i%2==1) s=s+1.0/ (2*i-1); Else s=s-1.0/ (2*i-1); Printf (%.4f, s); } //5, mathematical formula 1-1/2+1/3-1/4+1/5-1/6+... Value of +1/99-1/100. (4 to four after five decimal places) #include stdio.h Void, main () { Int i; Float s=0; For (i=1; i=100; i++) If (i%2==1) s=s+1.0/i; Else s=s-1.0/i; Printf (%.4f, s); } //6 when n=100 is calculated, S= (1-1/2) + (1/3-1/4) +...... The value of (1/ (2n-1) -1/ (2n)). Requirements: press four Five into the way, accurate to third decimal places. #include stdio.h Void, main () { Int i; Float s=0; For (i=1; i=100; i++) S=s+1.0/ (2*i-1) -1.0/ (2*i); Printf (%.3f, s); } //7 is known as S=1+1/ (1+2) +1/ (1+2+3) +... +1/ (1+2+3+... +N) when the value of N is 50, the value of S is determined. Requirement: press four Five into the way, accurate to fourth decimal places. #include stdio.h Void, main () { Int, I, t=0; Float s=0; For (i=1; i=50; i++) {t=t+i; S=s+1.0/t;} Printf (%.4f, s); } //8 asks Y=1-1/2+1/3-1/4+1/5... The sum of the first 30. Requirement: press four Five into the way, accurate to second decimal places #i