C++第二章习题解答（国外英文资料）.docVIP

C++第二章习题解答（国外英文资料） Chapter ii. Basic control structure programming problem First. Basic concepts and basic knowledge test 2.1 program reading 2.1.1 has instructions: Int a is equal to 3, and b is equal to 100; The following circular statement is executed (1), and the values of a and b are (2), (3). While (b/a 5) { If (b - a 25) a + +; Else b / = a; } Answer: This problem examines the concepts of the students. Tracking: a. b B/a. cycles B - 3 100 33 one 97 4 100 25 2 96 5 100 20 3 95 ... ... ... ... ... 15 100 6 13 85 16 100 6 14 84 17 100 5 stop (1) 14 (2) 17 (3), 100 2.1.2 has instructions: Int x, y, n, k; The function of the following segment is the alternative answer (1), when n = 10, x = 10 prints (2). Cin x n. K = 0; Do { / x = 2; K++; } while (k n); Y = 1 + x; K = 0; Do { Y = y * y; K++; } while (k n); Cout y endl; Alternate answers: A. b. b. c. d. Answer: The first loop makes x a: Y be:. The second loop makes y a: (1) B And if you think about it, when x is equal to 4 times 2, thats 0, so 0 (2) 1 See the program section below: If (num = = 1) cout Alpha; Else if (num = = 2) cout Bata; Else if (num = = 3). Else cout Delta; When the value of num is 1, 2, and 3, the output of the program segment is (1), (2), (3). Answer: Check conditional statements and string output concepts: (1) Alpha (2) the Bata (3) the Gamma The values of m and k are (1) and (2) after the following segment is executed. Int j, k; For (k = 1, m = 0; k = 50; k + +) {. If (m, = 10) break; If (m % 2 = = 0) { M + = 5; The continue; } M - = 3; } Answer: note the use of the continue statement The initial value M = 0 K = 1, After the first cycle M = 5 K = 2 After the second cycle M = 2 K = 3 After the third cycle M = 7 K = 4 After the fourth cycle M = 4 K = 5 After the fifth cycle M = 9 K = 6 After the 6th cycle M = 6 K = 7 After the seventh cycle M = 11 K = 8 Eighth cycle M = 11 end K is equal to 8, and k + + is not done (1) 11 (2) 8 Second. Programming and comprehensive exercise