6-7讲解.pptVIP

while((c=getchar())!=‘\n’) {switch(c-’2’) { case 0: case 1:putchar(c+4); case 2:putchar(c+4);break; case 3:putchar(c+3); default:putchar(c+2);break; } } printf(“\n”);;int func(int a,int b) {int c; c=a+b;return c; } main() {int x=6,y=7,z=8,r; r=func((x--,y++,x+y),z--); printf(“%d\n”,r); } a=13 b=8;main() {int i=2; p=f(i,i+1); } int f(a=2,b=3) {int c; c=a; if (ab) c=1; else if(a==b) c=0; else c=-1; return(c); };fun(int a,int b,int c) {c=a*b; return(c); } main() {int c; fun(2,3,c); printf(“%d”,c); };double f(int n) {int i;double s; s=1.0; for(i=1;i=2;i++) s=s+1.0/i; return s; } main() {int i,m=3;double a=0; for (i=0;im;i++) a=a+f(i); printf(“%f\n”,a); };fun6(unsigned num) {unsigned k=1; do {k=k*(num%10);num=num/10; } while(num); return k; } main() {unsigned n=26; printf(“%d\n”,fun6(n)); };double sub(double x,double y,double z) {y=y-1.0;z=z+x;return z;} main() {double a=2.5,b=9.0; printf(“%f\n”,sub(b-a,a,a)); } sub(6.5,2.5,2.5) y=1.5 z=9.0 ;int fun2(int a,int b) {int c; c=(a*b)%3;return c; } int fun1(int a,int b) {int c; a=a+a;b=b+b;c=fun2(a,b); return c*c; } main() {int x=11,y=19; printf(“%d\n”,fun1(x,y)); };