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Can groupwise density be much bigger than the non-dominating number
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7
GROUPWISE DENSITY CANNOT BE MUCH BIGGER THAN
THE UNBOUNDED NUMBER
SAHARON SHELAH
Abstract. We prove that g (the groupwise density number) is smaller or
equal to b+, the successor of the minimal cardinality of an unbounded subset
of ωω.
1. Introduction
In the present note we are interested in two cardinal characteristics of the con-
tinuum, the unbounded number b and the groupwise density number g. The former
cardinal belongs to the oldest and most studied cardinal invariants of the contin-
uum (see, e.g., van Douwen [9] and Bartoszyn?ski and Judah [2]) and it is defined
as follows.
Definition 1.1. (a) The partial order ≤Jbdω on
ωω is defined by
f≤Jbdω g if and only if (?N ω)(?n N)(f(n) ≤ g(n)).
(b) The unbounded number b is defined by
b = min{|F| : F ? ωω has no ≤Jbdω –upper bound in
ωω}.
The groupwise density number g, introduced in Blass and Laflamme [4], is per-
haps less popular but it has gained substantial importance in the realm of cardi-
nal invariants. For instance, it has been studied in connection with the cofinality
c(Sym(ω)) of the symmetric group on the set ω of all integers, see Thomas [8] or
Brendle and Losada [5]. The cardinal g is defined as follows.
Definition 1.2. (a) We say that a family A ? [ω]?0 is groupwise dense when-
ever:
? B ? A ∈ A, B ∈ [ω]?0 implies B ∈ A, and
? for every increasing sequence 〈mi : i ω〉 ∈ ωω there is an infinite set
U ? ω such that
?
{[mi,mi+1) : i ∈ U} ∈ A.
(b) The groupwise density number g is defined as the minimal cardinal θ for
which there is a sequence 〈Aα : α θ〉 of groupwise dense subsets of [ω]?0
such that
(
?B ∈ [ω]?0
)(
?α θ
)(
?A ∈ Aα
)(
B 6?? A
)
.
(Recall that for infinite sets A and B, A ?? B means A \B is finite.)
The unbounded number b and groupwise density number g can be in either order,
see Blass [3] and Mildenberger and Shelah [7], [6]. However, as we show in Theorem
2.2, g cannot be bigger than b+.
Date: August 20
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