冈萨雷斯数字图像处理第二版所有习题答案.pdfVIP

Digital Image Processing Second Edition Problem SolutionsStudent Set Rafael C. Gonzalez Richard E. Woods Prentice Hall Upper Saddle River, NJ 07458 /gonzalezwoods or ii Revision history 10 9 8 7 6 5 4 3 2 1 c Copyright °1992-2002 by Rafael C. Gonzalez and Richard E. Woods 1 Preface This abbreviated manual contains detailed solutions to all problems marked with a star in Digital Image Processing, 2nd Edition. These solutions can also be downloaded from the book web site (). 2 Solutions (Students) Problem 2.1 The diameter, x, of the retinal image corresponding to the dot is obtained from similar triangles, as shown in Fig. P2.1. That is, (d=2) (x=2) = 0:2 0:014 which gives x = 0:07d. From the discussion in Section 2.1.1, and taking some liberties of interpretation, we can think of the fovea as a square sensor array having on the order of 337,000 elements, which translates into an array of size 580 £580 elements. Assuming equal spacing between elements, this gives 580 elements and 579 spaces on a line 1.5 mm long. The size of each element and each space is then s = [(1:5mm)=1; 159] = 1:3 £10¡6 m. If the size (on the fovea) of the imaged dot is less than the size of a single resolution element, we assume that the dot will be invisible to the eye. In other words, the eye will not detect a dot if its diameter, d, is such t